00:01
In problem number 17, it says a new curing process developed for a certain type of cement results in a mean compressive strength of 5 ,000 kilograms per square centimeter with a standard deviation of 120 kilograms.
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To test the hypothesis that mu equals 5 ,000 against the alternative, mu is less than 5 ,000.
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A random sample of 50 pieces of cement is tested.
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The critical region is defined to be x bar is less than 4970.
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So here i have basically everything written down that we need.
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The population mean is 5 ,000, standard deviation is 120, and the sample size is 50.
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And then the critical region means that's where we're going to reject.
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So if x bar is less than 4970, then we're going to reject.
00:43
So the probability of a type 1 error is that we reject h0, given that h0 is true.
00:50
So we're finding the probability, well, the only way we can reject is if x bar is less than 4970.
00:55
So we're finding the probability that x bar is less than 4970, given that the mean is in fact 5 ,000.
01:04
Okay, so for this, if we draw a little curve, the mu is 5 ,000, and here we have 4970 somewhere over here.
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And we're going to shade, we're going to find this little area here.
01:16
So we do the normal cdf, the normal distribution, so cdf, of negative infinity, all the way up to 4970, and the mean is 5 ,000.
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And the standard deviation, now we're going to use the central limit theorem here.
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It's going to be 120, which is the standard deviation of the population, divided by the square root of your sample size.
01:39
So 120 divided by square root of 50.
01:42
Okay, so from there, you're in your calculator, so we'll go second vars or in any sort of software, or you can convert them to z scores and use a table.
01:50
That's always, you know, possibility.
01:53
A little harder, though.
01:54
So negative e99 will be our lower bound, 49, 70 will be our upper bound.
02:02
The mean is 5 ,000, and the standard deviation is 120 divided by square root of 50.
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So the alpha, the probability of a type 1 error, is about 0 .0385.
02:28
Part b, we're finding the beta, which is the probability of a type 2 error.
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So that means that h not is false and we're going to fail to reject.
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And we're finding beta for the alternatives, mu equals 4970 and mu equals 4960.
02:46
Okay, so 4970, that is where our cutoff point was...