00:01
Hey, everybody.
00:01
So this one's asking, find the mole fractions, the mixture gas constant and the mixture heat capacities for the new refrigerant.
00:08
So for this, we have r equals 32.
00:14
R equals 1, i mean r25 and r134a.
00:21
Okay.
00:23
And for this, we need to find the ci.
00:26
And the ci for this is 0 .23.
00:31
0 .25 and 0 .52.
00:36
Okay.
00:37
Next, we need to find the maths.
00:40
Okay, and we get 50 .2.
00:43
And you can find this again in your book.
00:46
So 120 .022 and 102 .03.
00:53
Okay.
00:55
And now we need to do the ci divided by mi.
00:58
And obviously this over this is going to be 0 .004 again 0 .00208 and 0 .00509.
01:17
Okay.
01:20
Now we find the mole fraction and this is just going to be 0 .3809.
01:31
And this is going to be 0 .1797 and this is going to be 0 .4399.
01:43
And just in case you guys don't remember, what we're doing for the y initial is looking at c -o -m -i divided by the epsilon of the c -i -m -i.
02:01
Okay? and so this is one of your answers.
02:09
Now for your r.
02:11
M.
02:12
And so for your mix, okay, we have 0 .23 times 52 .024 plus 0 .25 times 120.
02:30
Point, see if i, oops, i did slightly wrong, but i apologize, is we're going to times it by the rate.
02:47
So your rate of here is going to be 0 .1548 plus 0 .2525 times the rate, so 0 .06 ,27, plus 0 .5 .5...