00:01
We're told that it is assumed that the average brown trout's iq is 4, but that we think it is actually higher.
00:08
So from that part of the question, we know that we have an alternative hypothesis is that the mean is greater than 4.
00:18
And therefore, the null hypothesis is that the mean is at most 4.
00:27
And we're also given a sample of 12 brown trout along with their iqs.
00:32
So we have a sample size of 12.
00:34
And we're asked to conduct a hypothesis test of our belief that brown trout have an iq higher than 4.
00:40
So they don't give us a significance level to test our claim, so we can assume one ourselves.
00:45
We'll say let's do this at the significance level of 0 .05.
00:51
So from the 12 sample data that we are given in the question, you can use a calculator or a mathematical spreadsheet to calculate the sample average, and that is 4 .92.
01:05
And we're not given the population standard deviation, so we'll calculate the sample standard deviation, and that comes out to 1 .62.
01:16
So let's use the critical value approach to test our claim.
01:20
And the question of how are sample averages distributed, since we don't have the population standard deviation, but we do have the sample standard deviation, our sample averages are distributed according to the t distribution.
01:35
So using the critical value approach, we want to find, a critical value...