Question
A normal $\mathrm{KCl}$ solution contains $175 \mathrm{mEq} / \mathrm{L}$ each of $\mathrm{K}^{+}$ and $\mathrm{Cl}^{-} .$ How many moles each of $\mathrm{K}^{+}$ and $\mathrm{Cl}^{-}$ are in $2.00 \mathrm{~L}$ of the $\mathrm{KCl}$ solution?
Step 1
The volume of the solution is $2.00 \, \text{L}$ and the concentration of $\text{K}^{+}$ and $\text{Cl}^{-}$ is $175 \, \text{mEq/L}$. Show more…
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Solutions
Electrolytes and Nonelectrolytes
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