Question
A nucleus ${ }_{Z} X^{A}$ emits an $\alpha$-particle. The resultant nucleus emits a $\beta^{+}$particle. The respective atomic and mass numbers of the final nucleus will be(a) $Z-3, A-4$(b) $Z-1, A-4$(c) $Z-2, A-4$(d) $Z, A-2$
Step 1
It emits an $\alpha$-particle which is represented as ${ }_{2} He^{4}$. The atomic number of the $\alpha$-particle is 2 and the mass number is 4. Show more…
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