00:01
Okay, so in this question, they tell us that the k constant, lambda, is 4 .28 times 10 to negative 4 per hour or it's hour to negative 1.
00:15
And then they tell us that the disintegration per second, or a, is equal to 3 .14 times 10 to 5 per second or second to negative 1.
00:27
Right, so we see that the disintegration is in per second.
00:32
So we want to convert this per hour into per second.
00:36
So how can we do that? so we do 4 .28 times 10 to negative 4 per hour.
00:45
Right, so we have one hour is equal to 16 minute.
00:56
And one minute is equal to 62nd.
01:01
When we plug that into the accurate, we should get 1 .189 times.
01:05
Times 10 to negative 7 per second...