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A number $ a $ is called a fixed point of a function $ f $ if $ f(a) = a $. Prove that if $ f'(x) \not= 1 $ for all real numbers $ x $, then $ f $ has at most one fixed point.
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Fixed point couldn't exist more than 1
Calculus 1 / AB
Calculus 2 / BC
Applications of Differentiation
The Mean Value Theorem
Missouri State University
In mathematics, the volume of a solid object is the amount of three-dimensional space enclosed by the boundaries of the object. The volume of a solid of revolution (such as a sphere or cylinder) is calculated by multiplying the area of the base by the height of the solid.
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A number a is called a fix…
A number $a$ is called a f…
A number $c$ is called a f…
A fixed point of a functio…
so we're showing that F of X is equal to acts. That's only one solution is, uh, derivative of X is not equal to one. We have the function G of acts. We're gonna make it equal to F X minus. That's then we have the derivative of G of X is equal to the derivative of EPA VAX minus one is not equal to zero. Then we're gonna apply rules. Zero. You see that G FX has only 10 so f of X equals acts passed only one solution.
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