Question
A one-product firm estimates that its daily total cost function (in suitable units) is $C(x)=x^{3}-6 x^{2}+13 x+15$ and its total revenue function is $R(x)=28 x .$ Find the value of $x$ that maximizes the daily profit.
Step 1
So, we have: \[P(x) = R(x) - C(x) = 28x - (x^{3}-6x^{2}+13x+15)\] Show more…
Show all steps
Your feedback will help us improve your experience
Adrian Co and 77 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
thoughtful
A one-product firm estimates that its daily total cost function (in suitable units) is: C(x) = x^3 - 6x^2 + 13x + 15 and its total revenue function is: R(x) = 28x Select the value of x that maximizes the daily profit. x=1 x=5 x=-1 x=-5
A one-product firm estimates that its daily total cost function (in suitable units) is C(x) = 56,000 + 85x and its total revenue function is R(x) = 345x - 0.2x^2. Find the value of x that maximizes the daily profit.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD