Question
A parallel plate capacitor consists of two circular plates each of radius $12 \mathrm{~cm}$ and separated by $5.0 \mathrm{~mm}$. The capacitor is being charged by an external source. The charging is being charged and is equal to $0.15 \mathrm{~A}$. The rate of change of potential difference between the plates will be(A) $8.173 \times 10^{7} \mathrm{~V} / \mathrm{s}$(B) $7.817 \times 10^{8} \mathrm{~V} / \mathrm{s}$(C) $1.873 \times 10^{9} \mathrm{~V} / \mathrm{s}$(D) $3.781 \times 10^{10} \mathrm{~V} / \mathrm{s}$
Step 1
Step 1: The rate of change of potential difference between the plates of a capacitor can be given by the formula $\frac{dV}{dt} = \frac{I}{C}$, where $I$ is the current and $C$ is the capacitance of the capacitor. Show more…
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