00:01
So this question belongs to the electromagnetic wave in which we have given a parallel plate capacitor of radius capital r equals to 6 .0 centimeter that is equals to 0 .06 meter and capacity equals to 100 picof ferret that is 100 multiplied and to the power minus 12 ferret.
00:18
The capacitance is connected to vrms equals to 230 volt of ac supply with angular frequency omega equals to 300 radian per second okay so for the part a of the question we have to determine the rms value of the conduction current okay so we can write here that i rms this is equals to vrms divided by capacitive reactance xc okay and vrms divided by xc is 1 by omega c so we get from here vrms multiplied by omega c so, substituting value, so irms will be equals to 230 multiplied by omega, which is 300 multiplied by c, which is 100 multiplied by 10 to the power minus 12 ferret.
01:07
So from here after solving, irms, this is equals to 6 .9 microamper.
01:14
So this becomes the answer for the part a of the problem, okay? now moving to the part b in which we have to determine is this conduction current ic is equals to id or not.
01:27
So we can write that this conduction current are always equal.
01:31
So the answer for this problem is yes.
01:35
The conduction current and displacement current both are equal in the capacitor at any time.
01:41
Now moving to the part c in which we have to calculate the amplitude of magnetic field b at a point 3 cm from the distance between them...