A parallel-plate capacitor has charge $q$ and plate area $A .$
(a) By finding the work needed to increase the plate separation
from $x$ to $x+d x,$ determine the force between the plates. (Hint: See Eq. $8-22 .$ ) (b) Then show that the force per unit area (the electrostatic stress) acting on either plate is equal to the energy density $\varepsilon_{0} E^{2} / 2$ between the plates.