Question
A parallel-plate capacitor has square plates $10 \mathrm{cm}$ on a side and $0.50 \mathrm{cm}$ apart. The voltage across the plates is increasing at 220V/ms. What's the displacement current in the capacitor?
Step 1
The displacement current $I_d$ is given by the equation: \[I_d = \epsilon_0 \frac{d\Phi_E}{dt}\] where $\epsilon_0$ is the permittivity of free space and $\frac{d\Phi_E}{dt}$ is the rate of change of electric flux. Show more…
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A parallel-plate capacitor has square plates $10 \mathrm{cm}$ on a side and $0.50 \mathrm{cm}$ apart. The voltage across the plates is increasing at 220 V/ms. What's the displacement current in the capacitor?
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