00:01
In this question we have been given a parallel plate capacitor which has a square plates.
00:08
So this is a parallel plate capacitor and it has square plates.
00:13
So since the length of the plates have been given to us, so length of the plate is given to us as 8 .20 into 10 raised to the power minus 2 meters, we can take out the area of the plate.
00:26
So area of the plate will become l squared.
00:30
This will give us the answer as 67 .24 into 10 raised to the power minus 4 meters square.
00:37
So this is the area of the plate.
00:39
The distance between the plates is given to us as 1 .3 into 10 ratio to the power minus 3 meters.
00:46
Now we have to find out two things in this.
00:49
So the first thing is the capacitance.
00:52
So let's see how we can find out the capacitance.
00:54
So we know c is equal to epsilon knot a by d.
01:00
And we have been given that it's air, so there is no dialectic constrain.
01:04
So we'll put in the value, so this is 8 .85 into 10 raised to the power minus 12, into the area of the plates will be 67 .24 into 10 raised to the power minus 4...