00:01
In this problem a parallel plate capacitor is charged and then disconnected from a battery and we have to find out the fraction by which the stored energy changes when the plate separation is doubled.
00:19
So let us suppose the initial capacitance is c which is equal to a epsilon0 upon d.
00:28
A is the area of plates, epsilon0 is the constant and d is the separation of plates.
00:37
And initially the battery gives charge q to the capacitor.
00:43
Now when the capacitor is disconnected the new capacitance after the separation is doubled will be equal to a epsilon0 upon 2d because the separation is now twice the initial separation.
01:03
This can be written as half and a epsilon0 upon d is the original capacitor.
01:12
So the new capacitance is half of the original capacitance.
01:20
Now initial energy is equal to half q square upon c.
01:28
This is the energy of the capacitor with charge q and capacitance c.
01:35
Now when the battery is disconnected and plate separation is doubled the new energy will be half q square...