A parallel-plate capacitor is connected to a battery that...

A parallel-plate capacitor is connected to a battery that imposes
a potential difference $V$ between its plates. If a dielectric slab is inserted between the plates, what happens to (a) the potential difference, (b) the capacitance $C$, and (c) the capacitor charge $Q$ ?

Key Concepts

Parallel-Plate Capacitor

A parallel?plate capacitor is an arrangement of two conducting plates separated by a distance, which stores electrical energy in an electric field. Its capacitance depends primarily on the area of the plates, the separation distance, and the properties of the medium between them.

Battery Connection and Constant Voltage

When a capacitor is connected to a battery, the battery fixes the voltage across the capacitor's plates. This means that regardless of changes in other parameters, such as the capacitance, the potential difference remains constant as long as the battery is connected.

Dielectric Materials

A dielectric is an insulating material that, when placed between the plates of a capacitor, becomes polarized in the presence of an electric field. This polarization decreases the effective field between the plates, resulting in an increase in the capacitor's capacitance.

Charge Redistribution Due to Capacitance Change

In a constant voltage scenario, such as when a capacitor is connected to a battery, any increase in capacitance (for example, due to inserting a dielectric) leads to the charging of the capacitor with additional charge. The battery supplies this extra charge to maintain the fixed potential difference across the plates.

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