Question
A particle executes SHM between $x=-A$ to $x=+A$. The time taken for it to go from 0 to $A / 2$ is $T_{1}$ and to go from $A / 2$ to $A$ is $T_{2}$ then $T / T_{2}$ is(a) 2(b) $1 / 2$(c) 4(d) $1 / 4$
Step 1
The displacement of a particle executing SHM is given by $x=A\sin(\omega t)$, where $\omega$ is the angular frequency and $t$ is the time. Show more…
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