Question
A particle executing simple harmonic motion wion an amplitude $A$ and angular frequency $\omega$. The ratio of maximum acceleration to the maximum velocity of the particle is(a) $\omega A$(b) $\omega^{2} \mathrm{~A}$(c) $\omega$(d) $\frac{\omega^{2}}{A}$
Step 1
Step 1: We know that the maximum velocity $V_{max}$ in simple harmonic motion is given by $V_{max} = \omega A$, where $\omega$ is the angular frequency and $A$ is the amplitude. Show more…
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Oscillations and Waves
Section A
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