A particle has a charge of $+1.5 \mu \mathrm{C}$ and moves from point $A$ to point $B,$ a distance of $0.20 \mathrm{m}$. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at $A$ and at $B$ is $\mathrm{EPE}_{A}-\mathrm{EPE}_{B}=$ $+9.0 \times 10^{-4} \mathrm{J} .$ (a) Find the magnitude and direction of the electric force that acts on the particle.
(b) Find the magnitude and direction of the electric field that the particle experiences.