Question
A particle is acted upon by a force $F=k x,(k>0)$, where $x$ is displacement of particle. If potential energy at origin is zero, then the potential energy of the particle varies with $x$ as
Step 1
We also know that force is equal to the negative derivative of potential energy with respect to displacement, i.e., $F=-\frac{dU}{dx}$. Show more…
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A particle is placed at the origin and a force $F=k x$ is acting on it (where $k$ is a positive constant). If $U(0)=0$, the graph of $U(x)$ versus $x$ will be, figure (where $U$ is the potential energy function) [UP SEE 2004]
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Round 2
A particle is placed at the origin and a force $\mathrm{F}=\mathrm{kx}$ is acting on it $($ Where $\mathrm{K}$ is positive constant) If $\mathrm{U}(\mathrm{o})=0$, which one of the following graph of $\mathrm{U}(\mathrm{x})$ versus $\mathrm{x}$. (where $\mathrm{U}$ is the potential energy function)
The potential energy of a particle with displacement X is U(X). The motion is simple harmonic, when (K is a positive constant)
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