Question
A particle is acted upon by a force $F=k x,(k>0)$, where $x$ is displacement of particle. If potential energy at origin is zero, then the potential energy of the particle varies with $x$ as
Step 1
We also know that force is equal to the negative derivative of potential energy with respect to displacement, i.e., $F=-\frac{dU}{dx}$. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle is placed at the origin and a force $F=k x$ is acting on it (where $k$ is a positive constant). If $U(0)=0$, the graph of $U(x)$ versus $x$ will be, figure (where $U$ is the potential energy function) [UP SEE 2004]
Work, Energy and Power
Round 2
A particle is placed at the origin and a force $\mathrm{F}=\mathrm{kx}$ is acting on it $($ Where $\mathrm{K}$ is positive constant) If $\mathrm{U}(\mathrm{o})=0$, which one of the following graph of $\mathrm{U}(\mathrm{x})$ versus $\mathrm{x}$. (where $\mathrm{U}$ is the potential energy function)
The potential energy of a particle with displacement X is U(X). The motion is simple harmonic, when (K is a positive constant)
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD