00:01
For this question we are given a particle in a potential square well and within the square well there is also additional potential that is described by the second equation over here now we're given that this is the wave function that describes the particle and we want to find what is the energy so energy can be described using the shuringer's equation so what we want to do over here in order to find e, we want to substitute in what is our side as well as our potential into this expression, and then hopefully get a term that is a constant multiplied by the wave function and this constant must correspond to the energy.
01:04
So let us start by finding out what is our second derivative of the wave function.
01:13
So we differentiate our wave function once, differentiate again.
01:48
Now we can put everything into the left -hand side of the shorninger's equation.
02:11
So we add the potential over here, multiplied by the wave function, which is a times 1 minus x squared over l squared.
02:33
Now if you are quick to notice, you should be able to identify that the bottom denominator for this particular term we can actually divide or factor out l square.
02:50
If you factor out of l square, we will get l to the power 4 outside.
02:55
But inside, you'll become 1 minus x square over l square which is the same term as the numerator which we can then divide away right so after simplifying this is what we have left now there should be quite a familiar term which you can all the common factors which you can just bring out so the common factors are a h bar square m and l square.
04:04
What we have left remaining is 1 minus x squared over l square.
04:12
And this should look very familiar to you.
04:17
This is just hbar square over m l square times the wave function side.
04:27
And this is exactly what we needed...