Question
A particle is moving with a constant angular acccleration $\alpha=4 \mathrm{rad} / \mathrm{scc}^{2}$ in a circular path. At timc $t=0$ the particle was at rest. Find the time at which the magnitudes of centripctal acceleration and tangential acccleration are cqual
Step 1
The final angular velocity $\omega$ at any time $t$ can be calculated using the equation of motion: \[\omega = \omega_{0} + \alpha t\] Substituting the given values, we get: \[\omega = 0 + 4t = 4t\] Show more…
Show all steps
Your feedback will help us improve your experience
Nidhi Singhi and 52 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle is moving with a constant angular acceleration of 4 rad/s2 in a circular path. At t = 0, particle was at rest. Find the time at which the magnitudes of centripetal acceleration and tangential acceleration are equal.
A particle is moving with a constant angular acceleration of $4 \mathrm{rad} / \mathrm{s}^{2}$ in a circular path. At $t=0$, particle was at rest. Find the time at which the magnitudes of centripetal acceleration and tangential acceleration are equal. $\begin{array}{llll}\text { (A) } 1 \mathrm{~s} & \text { (B) } 2 \mathrm{~s} & \text { (C) } \frac{1}{2} \mathrm{~s} & \text { (D) } \frac{1}{4} \mathrm{~s}\end{array}$
A particle is moving along a circular path having a radius of 4 in. such that its position as a function of time is given by $\theta=\cos 2 t,$ where $\theta$ is in radians and $t$ is in seconds. Determine the magnitude of the acceleration of the particle when $\theta=30^{\circ}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD