Problem

A particle is moving with the given data. Find th…

01:41

Problem 63 Hard Difficulty

A particle is moving with the given data. Find the position of the particle.

$ a(t) = 10\sin t + 3\cos t $, $ \quad s(0) = 0 $, $ \quad s(2\pi) = 12 $

Name: a particle is moving with the given data find the position of the particle at 10sin t 3cos t quad s0
Uploaded: 2019-11-18
Duration: 1 min 37 s
Channel: Numerade
Description: A particle is moving with the given data. Find the position of the particle. $ a(t) = 10\sin t + 3\cos t $, $ \quad s(0) = 0 $, $ \quad s(2\pi) = 12 $

Answer

$$
s(t)=-10 \sin t-3 \cos t+\frac{6}{\pi} t+3
$$

Discussion

You must be signed in to discuss.

Top Calculus 2 / BC Educators

Grace H.

Anna Marie V.

Campbell University

Heather Z.

Oregon State University

Michael J.

Idaho State University

Watch More Solved Questions in Chapter 4

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

Problem 52

Problem 53

Problem 54

Problem 55

Problem 56

Problem 57

Problem 58

Problem 59

Problem 60

Problem 61

Problem 62

Problem 63

Problem 64

Problem 65

Problem 66

Problem 67

Problem 68

Problem 69

Problem 70

Problem 71

Problem 72

Problem 73

Problem 74

Problem 75

Problem 76

Problem 77

Problem 78

Problem 79

Video Transcript

okay. Remember that acceleration is the derivative of lost piece of lost ease, the integral or anti derivative of acceleration. They're for V. A T. Thea anti derivative would be negative co signed t with three sign of tea, plus our constant A. You can also give it C or D. Any name really works and then position is the integral velocity. It's a night of signed team, as three co signed t plus a our first constant times TV Plus B, which is our second constant. Now we know as of 00 therefore us of zero, we can play again plus eight times zero plus b said equal to zero. This gives us b is equivalent to three and remember us of two pious 12 so passive to pie his negative ton sign to pie here minus three co sign to pa for us too. Hi plus three is equivalent to 12. Therefore, to pie eh equals 12 therefore is equivalent to sex over pi. Therefore, a final equation is us of cheese is negative. 10 cider T minus three co sign of tea Put six over pi T plus three

Amrita B.

Topics

Derivatives

Differentiation

Volume

Calculus: Early Transcendentals

Chapter 4

Applications of Differentiation

Section 9

Antiderivatives

Problem