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A particle is moving with the given data. Find th…

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Problem 61 Hard Difficulty

A particle is moving with the given data. Find the position of the particle.

$ a(t) = 2t + 1 $, $ \quad s(0) = 3 $, $ \quad v(0) = -2 $


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Wen Zheng

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Amrita Bhasin

Related Courses

Calculus 1 / AB

Calculus 2 / BC

Calculus: Early Transcendentals

Chapter 4

Applications of Differentiation

Section 9

Antiderivatives

Related Topics

Derivatives

Differentiation

Volume

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Video Transcript

So we're giving a particle with the following data acceleration that's a F. T equals two T plus one. So when we find its velocity velocity is going to be the anti derivative of acceleration. So it's going to be um t squared plus T. And then we're gonna have plus a constant. But we know that via zero is negative two. That means this is gonna be minus two. Our position function at safety, it's going to be able to t cube over three. Okay. Plus t squared over two and then we're going to have minus two T. And um plus a constant. But we know that s of zero is three. So that means our constant value is three. Therefore this is our final position function.

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Related Topics

Derivatives

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Top Calculus 2 / BC Educators
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Video Thumbnail

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Video Thumbnail

06:14

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A review is a form of evaluation, analysis, and judgment of a body of work, such as a book, movie, album, play, software application, video game, or scientific research. Reviews may be used to assess the value of a resource, or to provide a summary of the content of the resource, or to judge the importance of the resource.

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