Question
A particle is projected with initial velocity $u$ at an angle $\alpha$ above the horizontal, then variation of torque and angular momentum with time will be :
Step 1
The weight of the particle acts downward and the distance from the origin is given by $r$. The horizontal component of velocity is $u \cos \alpha$ and the vertical component is $u \sin \alpha$. Show more…
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A particle is projected with initial velocity $u$ at an angle $\alpha$ above horizontal then variation of torque $\tau$ and angular momentum $L$ about starting point, with time will be :
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Section B
A particle is projected with a velocity $u$, at an angle $\alpha$, with the horizontal. Time at which its vertical component of velocity becomes half of its net speed at the highest point will be (A) $\frac{u}{2 g}$ (B) $\frac{u}{2 g}(\sin \alpha-\cos \alpha)$ (C) $\frac{u}{2 g}(2 \cos \alpha-\sin \alpha)$ (D) $\frac{u}{2 g}(2 \sin \alpha-\cos \alpha)$
A particle of mass $m$ is projected from origin $O$ with spced $u$ at an angle $\theta$ with positive $x$ -axis. Positive $y$ -axis is in vertically upward dircction. Find the angular momentum of particle at any time $t$ about $O$ before the particle strikes the ground again.
Section A
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