Question
A particle leaves the origin with an initial velocity $\vec{v}=(3.00 \hat{\mathrm{i}}) \mathrm{m} / \mathrm{s}$ and a constant acceleration $\vec{a}=(-1.00 \hat{\mathrm{i}}$0.50$\hat{\mathrm{j}} ) \mathrm{m} / \mathrm{s}^{2} .$ When it reaches its maximum $x$ coordinate, what aits (a) velocity and (b) position vector?
Step 1
Substituting the given values, we get: \[ v_{x}=3.00 \, \mathrm{m/s} - 1.00 \, \mathrm{m/s^{2}} \cdot t \] \[ v_{y}=0.50 \, \mathrm{m/s^{2}} \cdot t \] Show more…
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A particle leaves the origin with an initial velocity $\vec{v}=(3.00 \hat{\mathrm{i}}) \mathrm{m} / \mathrm{s}$ and a constant acceleration $\vec{a}=(-1.00 \hat{\mathrm{i}}-$ $0.500 \hat{\mathrm{j}}) \mathrm{m} / \mathrm{s}^{2}$. When it reaches its maximum $x$ coordinate, what are its (a) velocity and (b) position vector?
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Particle Leaves Origin A particle leaves the origin with an initial velocity $\vec{v}_{1}=(3.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}$ and a constant acceleration $\vec{a}=$ $\left(-1.00 \mathrm{~m} / \mathrm{s}^{2}\right) \hat{\mathrm{i}}+\left(-0.500 \mathrm{~m} / \mathrm{s}^{2}\right) \hat{\mathrm{j}}$. When the particle reaches its maximum $x$ coordinate, what are (a) its velocity and (b) its position vector?
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