Question
A particle moves along the $x$ -axis so that its position at any time $t \geq 0$ is given by $x(t) .$ Find the velocity at the indicated value of $t.$$$x(t)=\sin ^{-1}\left(\frac{\sqrt{t}}{4}\right), \quad t=4$$
Step 1
We know that the derivative of $\sin^{-1}(t)$ is $\frac{1}{\sqrt{1-t^2}}$ and the derivative of $\sqrt{t}/4$ is $\frac{1}{8\sqrt{t}}$. Show more…
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