Question
A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement $x$ is proportional to [UP SEE 2007](a) $x^{2}$(b) $\mathrm{e}^{x}$(c) $x$(d) $\log e^{x}$
Step 1
Step 1: Given that the retardation is proportional to the displacement, we can write the equation of motion as \[a = -kx\] where \(a\) is the acceleration, \(k\) is a constant of proportionality, and \(x\) is the displacement. Show more…
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