Question
A particle moves on a curved path with constant speedv. The acceleration of the particle at $x=0$ is $2 a v^{2}$. The path of particle is:(a) straight line(b) parabolic(c) elliptical(d) none of these
Step 1
We can denote this acceleration as $A$ and the constant as $a$. So, we have $A = 2av^{2}$. Show more…
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