Question
A particle of mass ' $m$ ' and charge ' $q$ ' is accelerated through a potential difference of ' $V$ 'volt. Its energy is [UPSEAT 2001](a) $q V$(b) $m q V$(c) $\left(\frac{q}{m}\right) V$(d) $\frac{q}{m V}$
Step 1
Step 1: The energy of a charged particle accelerated through a potential difference is given by the formula: \[E = qV\] where: - \(E\) is the energy, - \(q\) is the charge of the particle, and - \(V\) is the potential difference. Show more…
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