A particle of mass $m$ is projected with velocity $v$ moving at an angle of $45^{\circ}$ with horizontal. The magnitude of angular momentum of projectile about point of projection when particle is at maximum height, is :
(a) zero
(b) $\frac{m v^{3}}{4 \sqrt{2} g}$
(c) $\frac{m v^{3}}{\sqrt{2} g}$
(d) $m \sqrt{2} g h^{3}$