00:01
Hello, we have problem number 98, which is a quite interesting problem.
00:06
It is given that the potential energy of a particle is given by an expression by an expression, and the particle is kept at x equal to 0, that is at the origin, and then given slide displacement, delta x in positive x direction, then forces acting on particle will displace it to we have to find out what will happen.
00:30
If this is x -exis, this is the origin so initially the particle is kept here with potential energy equal to x cube minus x squared by 2 x q minus x squared by 2 joles okay so it is given that if displacement is done by an amount delta x in positive x direction so the forces we have to calculate we have to find the force is acting on the particle will displace to in which direction.
01:11
So it is quite simple that we have to first find the equilibrium position.
01:15
Where is the equilibrium position? for that we have to differentiate this potential energy with respect to x.
01:23
This is 3x squared minus 2x by 2.
01:27
This will become 0...