A particle of mass $m$ (starting at rest) moves vertically upwards from the surface of earth under an external force $\vec{F}$ which varies with height $z$ as $\vec{F}-(2-\alpha z) m \vec{g}$, where $\alpha$ is a positive constant. If $H$ is the maximum height to which particle rises. Then
(a) $H-\frac{1}{\alpha}$
(b) Work done by $\vec{F}$ during motion upto $\frac{H}{2}$ is $\frac{3 m g}{2 \alpha}$
(c) $H-\frac{2}{\alpha}$
(d) Velocity of particle at $\frac{H}{2}$ is $\sqrt{\frac{g}{\alpha}}$