Question
A particle performing uniform circular motion has angular frequency is doubled and its kinetic energy halved, then the new angular momentum is [2003](A) $\frac{L}{4}$(B) $2 L$(C) $4 \mathrm{~L}$(D) $\frac{L}{2}$
Step 1
Step 1: The angular momentum (L) of a particle performing uniform circular motion is given by the formula: \[L = I \omega\] where I is the moment of inertia and \(\omega\) is the angular frequency. Show more…
Show all steps
Your feedback will help us improve your experience
Arpit Gupta and 94 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle performs uniform circular motion with an angular momentum $L$. If the frequency of a particle's motion is doubled and its kinetic energy is halved, the angular momentum becomes (a) $2 L$ (b) $4 L$ (c) $L / 2$ (d) $L / 4$
Rotational Motion
Round 1
A particle performing uniform circular motion has angular momentum $L$., its angular frequency is doubled and its $K . E$. halved, then the new angular momentum is $\{\mathrm{A}\} 1 / 2$ \{B $\} 1 / 4$ $\{\mathrm{C}\} 2 \mathrm{~L}$ $\{\mathrm{D}\} 4 \mathrm{~L}$
A particle performs uniform circular motion with an angular momentum $L$. If the frequency of particle motion is doubled and its K.E. is halved, the angular momentum becomes: (a) $2 L$ (b) $4 L$ (c) $\frac{L}{2}$ (d) $\frac{L}{4}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD