00:01
In this problem of motion along a straight line we have given a figure first i'm showing here.
00:06
So this is the figure and a particle starts from origin at t is equal to 0 and moves along the position positive x -axis.
00:16
A graph of velocity of the particle as a function of the time is shown here.
00:21
This is a velocity versus time t as vs is equals to this is 4 .0 meters per second.
00:30
We have to find what is the coordinate of the point of the time? the particle at t is equal to 5 seconds.
00:36
So we have to find the position at t is equal to 5 seconds.
00:42
So as we know that the graph of velocity versus time t gives the position.
00:48
So we have to find the area of this up to t is equal to 4 seconds.
00:52
So this area would be a1 and this area would be a2 from 2 to 4 seconds.
00:59
Now we have to find the position so x would be equals to a1 plus a2.
01:03
Now for a1 this is half multiplied with base so x is equal to half multiplied with base which is equal to 2 and height which is equal to 4.
01:14
Now a2 is a rectangle so this is 4 minus 2 which is 2 multiplied with this is 4.
01:22
Now when we solve it so x is equal to this is 4 plus 8 which is equal to here 12...