Question
A particle with mass $2.30 \mathrm{g}$ and charge $+10.0 \mu \mathrm{C}$ enters through a small hole in a metal plate with a speed of $8.50 \mathrm{m} / \mathrm{s}$ at an angle of $55.0^{\circ} .$ The uniform $\overrightarrow{\mathbf{E}}$ field in the region above the plate has magnitude $6.50 \times 10^{3} \mathrm{N} / \mathrm{C}$ and is directed downward. The region above the metal plate is essentially a vacuum, so there is no air resistance. (a) Can you neglect the force of gravity when solving for the horizontal distance traveled by the particle? Why or why not? (b) How far will the particle travel, $\Delta x,$ before it hits the metal plate?FIGURE CANT COPY
Step 1
The electric force is given by $F_e = qE$ and the gravitational force is given by $F_g = mg$, where $q$ is the charge of the particle, $E$ is the electric field, $m$ is the mass of the particle, and $g$ is the acceleration due to gravity. Show more…
Show all steps
Your feedback will help us improve your experience
Zulfiqar Ali and 76 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle with mass $2.30 \mathrm{g}$ and charge $+10.0 \mu \mathrm{C}$ enters through a small hole in a metal plate with a speed of $8.50 \mathrm{m} / \mathrm{s}$ at an angle of $55.0^{\circ} .$ The uniform $\overrightarrow{\mathbf{E}}$ field in the region above the plate has magnitude $6.50 \times 10^{3} \mathrm{N} / \mathrm{C}$ and is directed downward. The region above the metal plate is essentially a vacuum, so there is no air resistance. (a) Can you ignore the force of gravity when solving for the horizontal distance traveled by the particle? Why or why not? (b) How far will the $\Delta x,$ before it hits the metal plate?
A particle possessing q = 6.25 μC of charge and a mass of m = 6.55 g is fired at a speed of v = 255 cm/s between two horizontal charged plates of length L = 44.7 cm. Assume that the electric field between the plates is uniform and has a constant value of E = 2060 N/C, directed upwards. Calculate the distance y by which the charge falls below a straight-line path when it reaches the end of the plates. Assume a gravitational acceleration of g = 9.81 m/s^2. What field strength will allow the particle to pass between the plates along a straight path?
Two horizontal metal plates, each 10.0 cm square, are aligned 1.00 cm apart with one above the other. They are given equal-magnitude charges of opposite sign so that a uniform downward electric field of $2.00 \times 10^{3} \mathrm{N} / \mathrm{C}$ exists in the region between them. A particle of mass $2.00 \times$ $10^{-16} \mathrm{kg}$ and with a positive charge of $1.00 \times 10^{-6} \mathrm{C}$ leaves the center of the bottom negative plate with an initial speed of $1.00 \times 10^{5} \mathrm{m} / \mathrm{s}$ at an angle of $37.0^{\circ}$ above the horizontal. (a) Describe the trajectory of the particle. (b) Which plate does it strike? (c) Where does it strike, relative to its starting point?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD