00:01
Newton's second law applied to the penny along the y -axis.
00:04
We have the net force equalling the normal force minus the gravitational force equaling the mass times the acceleration in the y direction.
00:12
Now we know that the force, the net force is upward.
00:16
We can say at the bottom of the cycle.
00:23
And here we have a positive acceleration in the y direction.
00:27
So here then the normal force would be greater than the gravitation.
00:32
Force.
00:35
The speed is a maximum when passing through equilibrium, but here the accelerator, so we can say through the equilibrium position, we can say that the acceleration in the wide direction is equaling zero, and so the normal force is equaling m .g.
00:57
The critical point would be the highest point, where f -net points downwards at highest point in the cycle, we can say that then we have a negative acceleration in the wide direction, and if a becomes sufficiently negative, we have then that the normal force approaches zero -newton's, and then the penny is no longer in contact with the surface at the top.
01:30
So if we have a negative, if the negative acceleration in the wide direction becomes, significantly negative, the normal force approaches zero newton's, and there is nothing, essentially there's no force that is allowing the penny to stick to the surface...