Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

A person drags her 65 $\mathrm{N}$ suitcase along the rough horizontal floor by pulling upward at $30^{\circ}$ above the horizontal with a 50 $\mathrm{N}$ force. Make a free-body diagram of this suitcase.

see solution.

Physics 101 Mechanics

Chapter 4

Newton's Laws of Motion

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

Lectures

03:28

Newton's Laws of Motion are three physical laws that, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces. These three laws have been expressed in several ways, over nearly three centuries, and can be summarised as follows: In his 1687 "Philosophiæ Naturalis Principia Mathematica" ("Mathematical Principles of Natural Philosophy"), Isaac Newton set out three laws of motion. The first law defines the force F, the second law defines the mass m, and the third law defines the acceleration a. The first law states that if the net force acting upon a body is zero, its velocity will not change; the second law states that the acceleration of a body is proportional to the net force acting upon it, and the third law states that for every action there is an equal and opposite reaction.

04:16

In mathematics, a proof is a sequence of statements given to explain how a conclusion is derived from premises known or assumed to be true. The proof attempts to demonstrate that the conclusion is a logical consequence of the premises, and is one of the most important goals of mathematics.

01:18

An airline flight attendan…

02:31

woman at an airport is tow…

02:11

A woman is standing in an …

02:41

03:05

A woman at an airport is t…

04:58

A factory worker pushes ho…

02:26

01:21

You are pulling a suitcase…

03:40

A 63 -kg tightrope walker …

01:43

I have a suitcase. It's being drunk on the ground. Um, by an angle of 30 degrees above with the Force 50 Newtons, its weight in 65 Newton's first was dropped by diagram. I went ahead and started box S C stands for suitcase. Um and I mean that some I've seen. People will say that you're free body diagram can just consider doing like a line like that for the angle. Um, that is true. I like to I like to break this down always so 30 degrees, 50 Nunes. This means that there is a horizontal force of 50 co sign of 30 in a upward force of 50. Sign of 30 um, because we always think of drawing this as a right triangle where you have your co sign in your side anyway. And oh, and we also know that the floor has friction. The problem didn't say frictionless. So we have a negative ah, kinetic friction force. And then we have Ah, it's weight which is 65. Newton's put in the downward direction. We have a horizontal force. Of the 50 co sign of 30. I did. We have the normal fours and I believe in the problem so that technically that's done, we could calculate it'll force leaving. Problem just says that she's currently dragging it well, assuming she's dragging on the ground, that means that it is not being lifted up in the air at all. That means that elevation is remaining constant. That means that the some of why forces needs to equal zero and that means that But to do that means that Oh, and I forgot one other thing to read about the side of a normal four. So we don't know. Plus the 50 sign of 30. Yeah. So that means that we know that 65 Newtons of the downward direction needs to equal the normal fours plus the 50 sign of 30 um, in the northern direction and Newton's shot in, Uh oh, isolated wrong. And this is a normal That's an in for normal. There we go. Okay, that's better. So 65 Newtons needs equal the normal vector plus 50 side 30 Newton's because they used need to sum to zero. So these need to be equipment to each other. We're Do you have any vehicle drivers when I add because this is a negative. 65. So that would be the same number. Stay away. The positive post. Negative. Equal zero. Okay, which is actually get here. Yeah, because you would set them equal each other and then did that. Okay, so I said, this upstart, that kind of what? I wouldn't really weird. Certainly way of describing that. But we set these up because we know that they need to sum to zero. And if they need a sum to zero, that means the positive needs to be the exact opposite of negative. And that means that if we had an equal zero, you can add the negative other side that gets us this equation right here. This was trying to do so. The normal vector is equal to 65 new MMS minus 50. Sign of 30 new Nunes, which is equal to 65. Nunes, a sign of 30. Sign of 30 is 1/2. So minus 25 Newtons. So, uh 40 Well, five man, I've had a hard time. Guys, I am sorry. 5150 60 minus 20 Is 40 40. Nunes Wow! We're struggling. So a normal force of 40 Newtons is our normal force I don't know if that's necessary. Um, I mean, it's not wrong, but it's probably detailed the Nets surface problem, but I like to draw these things all broken down so I can answer questions.

View More Answers From This Book

Find Another Textbook

Numerade Educator

04:22

Blood pressure. Systemic blood pressure is defined as the ratio of two press…

02:50

Computer chips (Fig. 13$)$ etched on circular silicon wafers of thickness 0.…

06:45

$\bullet$ A copper pot with a mass of 0.500 $\mathrm{kg}$ contains 0.170 $\m…

03:00

If 25.0 g of the metal gallium melts in your hand (see Fig.14.14 , what …

07:02

$$ \begin{array}{l}{\text { Use Table } 3 \text { to estimate the total numb…

09:03

(III) Another experiment you can do also uses the radius of the Earth. The S…

01:57

There is a maximum depth at which a diver can breathe through a snorkel tube…

04:08

The plates of a parallel-plate capacitor are 2.50 $\mathrm{mm}$ apart, and e…

01:28

(II) Add $$ \left(9.2 \times 10^{3} s\right)+\left(8.3 \times 10^{4} s\right…

04:27

$\bullet$ Bicycling on a warm day. If the air temperature is the same as the…