Question
A person notices a mild shock if the current along a path through the thumb and index finger exceeds $80.0 \mu \mathrm{A} .$ Determine the maximum allowable potential difference without shock across the thumb and index finger for the following:a. a dry-skin resistance of $4.0 \times 10^{5} \Omega.$b. a wet-skin resistance of $2.0 \times 10^{3} \Omega.$
Step 1
0 \mu A$. We also know that the resistance of dry skin is $4.0 \times 10^{5} \Omega$. We can use Ohm's law, which states that the voltage (V) is equal to the current (I) times the resistance (R), or $V = IR$. Show more…
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A person notices a mild shock if the current along a path through the thumb and index finger exceeds $80 . \mu \mathrm{A}$ Compare the maximum possible voltage without shock across the thumb and index finger with a dry-skin resistance of $4.0 \times$ $10^{5} \Omega$ and a wet-skin resistance of 2.0 $\mathrm{k} \Omega$ .
A person notices a mild shock if the current along a path through the thumb and index finger exceeds $80 \mu \mathrm{A}$. Compare the maximum possible voltage without shock across the thumb and index finger with a dry-skin resistance of $4.0 \times 10^{5} \Omega$ and a wet-skin resistance of $2000 \Omega$.
A person notices a mild shock if the current along a path through the thumb and index finger exceeds 80 µA. Compare the maximum possible voltage without shock across the thumb and index finger with a dry-skin resistance of 4.0 ✕ 105 and a wet-skin resistance of 1500 . dry skin V wet skin V
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