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A person slaps her leg with her hand, bringing her hand to rest in 2.50 milliseconds from an initial speed of 4.00 $\mathrm{m} / \mathrm{s}$ . (a) What is the average force exerted on the leg, taking the effective mass of the hand and forearm to be 1.50 $\mathrm{kg}$ ? (b) Would the force be any different if the woman clapped her hands together at the same speed and brought them to rest in the same time? Explain why or why not.
(a) $F = - 2.40 \mathrm { kN }$(b) Yes.
Physics 101 Mechanics
Chapter 8
Linear Momentum and Collisions
Moment, Impulse, and Collisions
University of Michigan - Ann Arbor
Simon Fraser University
University of Winnipeg
McMaster University
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Okay, so here, in this question, the time she takes to bring her hands in graced is 2.5 minutes seconds. So that is it called a 2.5 return of the power minus three seconds. Now the issue of Speed Waas you is equal to four readers for a second. So what is there is force, given that the masses 1.5 visit so r e the masses, given as one fight easy. So force F would be equal to times until the regions in, well, a city upon a time So mass is 1.5 diversity tend This crumb, for to Gerald right? Certainly is only for the differences for on the genes in time is 2.5 into to follow minus three. This gents are too mean. Do 400 years. All right, so let's move on to the next part of the question in Barbie, the person's asked us the first be any different if the women glad. Clap her hands together. Well, Nordic Prince, Why? What because M is seen means constant the mass of Chinese person. The change in velocity again is from four to there, because that would ultimately come to rest, right? So, ladies, four minutes series for diversity in the scene. You know, it's a constant. And what about the time? Obviously, that should really so constant. So So f is seen. Hey. All right, so we have solved this question.
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