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A person with a black belt in karate has a fist that has a mass of 0.70 $\mathrm{kg}$ . Starting from rest, this fist attains a velocity of 8.0 $\mathrm{m} / \mathrm{s}$ in 0.15 $\mathrm{s}$ . What is the magnitude of the average net force applied to the fist to achieve this level of performance?

37 $\mathrm{N}$

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to solve this question, we have to discover what is the acceleration off the feast. And then we can apply Newton's second law to discover what is the force that was acting on the fist. So to discover it acceleration off the feast, we can use that simple equation. Definition off acceleration is a variation off velocity divided by the time it took for that variation to happen in the situation. The initial velocity zero and the final velocity is eight, so the variation in Velocity is eight, and the time it took is 0.15 seconds. Then this is the acceleration of the feast now, using Newton's second law. From these access, we can say that the net force acting on the X direction is given by the mass off the feast times. Its acceleration that the net force is given by 0.7 times eight, divided by 0.15 which results in approximately 37 nutrients

Brazilian Center for Research in Physics