A person's blood alcohol $\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{OH}\right)$ level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. The balanced equation is
$$
16 \mathrm{H}^{+}(a q)+2 \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\begin{array}{c}
\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(a q) \longrightarrow \\
4 \mathrm{Cr}^{3+}(a q)+2 \mathrm{CO}_{2}(g)+11 \mathrm{H}_{2} \mathrm{O}(l)
\end{array}
$$
If $35.46 \mathrm{~mL}$ of $0.05961 \mathrm{M} \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}$ is required to titrate $28.00 \mathrm{~g}$ of
plasma, what is the mass percent of alcohol in the blood?