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Hello.
00:01
So here we have our null hypothesis is that mu is equal to 3 % versus our alternative hypothesis that mu is greater than 3 % with our standard deviation.
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Sigma is going to be equal to 0 .4%.
00:15
And our sample size, n is equal to 64 pills.
00:20
And our sample mean x bar is equal to 3 .07 % with our significance level alpha equal to 0 .0 .0 .0 .5%.
00:32
So then to test this, we do not reject our null hypothesis since we get that our test statistic, z is going to be equal to 3 .07 minus 3 divided by 0 .4, divided by the square root of 64.
00:49
That's going to be equal to 1 .4, which is going to be less than 1 .645.
00:56
So therefore we have that x, we have x bar is 3 .07, which is less than x subc bar, which is 3 .082.
01:05
So we can conclude that the population mean impurity concentration then is equal to 3%.
01:17
And then for part b, we have the p value for this test is going to be the probability that z sub p is greater than 1 .4.
01:27
0 .4.
01:29
So from our table, that's going to be 0 .0808.
01:34
And then we have, for the next part here, the p value is going to be the probability of obtaining a value of test statistics as extreme or as or more extreme than the actual value obtained when the null hypothesis is true.
01:52
So if we suppose that mu is equal to 3 % versus our alternative, the mu is not equal to 3%, then the p value for our two -tailed test is going to be, well, two times the probability that the absolute value of x bar minus mu not divided by sigma over the square root of n is going to be greater than z sub p over two, such that we have that the null hypothesis mu is equal to mu not...