Question
A photographic flash unit consists of a xenon filled tube. It gives a flash of average power $2000 \mathrm{~W}$ for $0.04 \mathrm{~s}$. The fash is due to discharge of a fully charged capacitor of $40 \mu \mathrm{F}$. The voltage to which it is charged before a flash is given by the unit isa. $1500 \mathrm{~V}$b. $2000 \mathrm{~V}$c. $2500 \mathrm{~V}$d. $3000 \mathrm{~V}$
Step 1
This can be calculated using the formula: \[E = P \cdot t\] where \(E\) is the energy, \(P\) is the power, and \(t\) is the time. Substituting the given values, we get: \[E = 2000 \, \text{W} \cdot 0.04 \, \text{s} = 80 \, \text{J}\] Show more…
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