Given that the pharmacist has a 4.5% aqueous suspension of theophylline, we can calculate the amount of theophylline in 5 mL of this suspension:
$4.5\% = \frac{4.5}{100} = 0.045$
Amount of theophylline in 5 mL of the suspension = $0.045 \times 5 = 0.225$ mg
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