Question
A piece of aluminum has a volume of $1.4 \times 10^{-3} \mathrm{m}^{3} .$ The coefficient of volume expansion for aluminum is $\beta=69 \times 10^{-6}\left(\mathrm{C}^{\circ}\right)^{-1}$ . The temperature of this object is raised from 20 to $320^{\circ} \mathrm{C} .$ How much work isdone by the expanding aluminum if the air pressure is $1.01 \times 10^{5} \mathrm{Pa} ?$
Step 1
The initial temperature is 20 degrees Celsius and the final temperature is 320 degrees Celsius. So, the change in temperature is given by: \[ \Delta T = T_{final} - T_{initial} = 320^{\circ}C - 20^{\circ}C = 300^{\circ}C \] Show more…
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