00:01
This is question 70 from chapter 16 gases, and we are trying to find the total grams of sodium used in this reaction.
00:12
So the first thing we have to do is actually solve for the pressure of the hydrogen.
00:19
And they said the total pressure for this equation is one atmospheric pressure.
00:24
And then they said that sodium is at 0 .0313 atmosphere.
00:31
So when you subtract both of those, this is going to get your pressure for the h2.
00:35
So that's going to come up to 0 .9687 for the h2.
00:46
Okay, now that we do that, we can solve for moles, and we're going to be doing that by using the equation pv is equal to n r t.
01:01
And since we're solving for moles, it's going to be rewritten as n n equals p v times r t okay now that we have that we can plug it in so in is equal to the pressure that we just found for hydrogen so 0 .967 atm times the volume which they said was 246 milliliters but this has to be in liter so we're going to convert that by dividing by 1 ,000, so 0 .246 liters all over the gas constant, which is 0 .0826 liters times atmospheric pressure per mole times kelvin...