00:01
So here from the free biode diagram, we can, if we apply newton's second law in the x direction, we could see that then t -cosine of theta sub -1 would be equal to t -cosine of theta -2.
00:15
This is essentially telling us that theta -1 is equaling theta -sub -2.
00:22
We can then, from this figure here, second figure, we can see that then d -cosine of theta plus, l minus d, cosine of theta, would be equaling than d.
00:39
And we can then simplify l cosine of theta, equaling d.
00:47
And solving for theta, this would simply be equal to arc cosine of d over l, equaling arc cosine of 2 .0 meters divided by 3 .0 meters, giving us then 48 .19 degrees.
01:14
Now, we can determine the value of d.
01:17
We can say that then l sine of theta minus l, rather minus d.
01:27
This would then be multiplied by sine of theta minus d sine of theta is equal to h and so we can distribute and rearrange solve for d d is then going to be equaling to l sine of theta minus h this would be divided by two sine of theta we can apply newton second law in the y direction this would be equal to the mass time the acceleration in the wide direction.
02:06
We have translational equilibrium in the wide direction, so this will be equal to zero.
02:11
And we have two times the tension, sine of theta, minus mg, equaling zero.
02:19
So to solve for tension t, this would be equal to mg over two sine of theta...