Given that the pipe is cylindrical in shape, the cross-sectional area is circular. The formula for the area of a circle is $\pi r^2$, where $r$ is the radius. Substituting $r = 0.06 \mathrm{~m}$, we get:
\[A = \pi (0.06)^2 = 0.0113 \mathrm{~m}^2\]
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