00:01
We wish to calculate the compression work for the two cases and the final temperature of the system.
00:06
So for part a, we are given the pressure of the initial and final states, the pressure and the temperature of the initial and final states.
00:16
So initial pressure is 1 megapascal, and the initial temperature, t1, is 400 degrees celsius.
00:31
And if we go to our table, this corresponds to a specific volume.
00:35
Volume v1 of 0 .30661 cubic meters per kg.
00:48
Now the final state, we have the pressure again of 1 megapascal and a final temperature, t2, of 250 degrees celsius.
01:04
So this corresponds with a specific volume v2 of 0 .232 25 cubic meters per kg.
01:19
So now note that the pressure is constant during the process and so we can calculate the boundary walk as follows.
01:27
The boundary work wb is simply m times p times v1 minus v2.
01:36
So the mass of the a is 0 .6 kg or the mass of steam rather.
01:44
The pressure is constant.
01:49
So 1 megapascal is 1 ,000 kilopascals.
01:55
And that's multiplied by the difference in specific volume, which is 0 .30661 minus 0 .23275, and that's cubic meters per kg.
02:15
So doing the calculation, we get the boundary work to be 44 .3 kilojoules...