00:01
All right, guys, let us start with the answer of this question.
00:04
We've got v1 that is equal to 0 .01 cubic meter.
00:09
Then we've got t1 is equal to 290 kelvin.
00:13
We've got pressure, p is equal to 600 kilo -pastal, and we have w is equal to 54 kilo -jal.
00:23
Now we can calculate the mass from ideal gas equation, that is p to v1 is equal.
00:31
To m into r into t1 and where gas constant for the air is r is equal to 0 .287 kilojou per kg kelvin and m is equal to p into v1 divided by r into t1 we've got 600 into 0 .01 divided by 0 .287 into 290 is equal to 0 .072 meters.
01:10
So this is constant pressure process.
01:15
So isabaric process.
01:17
So work done is given by w is equal to w is equal to p into v2 minus v1 and we've got v2 is equal to w over p plus v1 is equal to 54 over 600 plus 0 .01.
01:42
And we've got v2 is equal to 0 .1 meter cube.
01:47
Using the charles law equation, we can calculate the final temperature...